Cho A=12x3y5z⋅(−4)yz2A = \dfrac{1}{2}x^{3}y^{5}z \cdot ( - 4)yz^{2}A=21x3y5z⋅(−4)yz2. Đơn thức AAA sau khi thu gọn là:
A=12x3y5z.(−4)yz2=12(−4)x3(y5.y)(z.z2)=−2x3y6z3A = \dfrac{1}{2}x^{3}y^{5}z.( - 4)yz^{2} = \dfrac{1}{2}( - 4)x^{3}(y^{5}.y)(z.z^{2}) = - 2x^{3}y^{6}z^{3}A=21x3y5z.(−4)yz2=21(−4)x3(y5.y)(z.z2)=−2x3y6z3
